x^2+y^2=c^2*(1+d*x^2*y^2)This curve shape was introduced by 2007 Edwards for the case d=1.
Technically, an Edwards curve is not elliptic, because it has singularities; but resolving those singularities produces an elliptic curve.
The neutral element of the curve is the point (0,c). The point (0,-c) has order 2. The points (c,0) and (-c,0) have order 4.
x=Z/X y=Z/Y
Projective coordinates [more information] represent x y as X Y Z satisfying the following equations:
x=X/Z y=Y/Z